2x^2+3x-38=4x-2

Solution for 2x^2+3x-38=4x-2 equation:

2x^2+3x-38=4x-2

We move all terms to the left:

2x^2+3x-38-(4x-2)=0

We get rid of parentheses

2x^2+3x-4x+2-38=0

We add all the numbers together, and all the variables

2x^2-1x-36=0

a = 2; b = -1; c = -36;
Δ = b2-4ac
Δ = -12-4·2·(-36)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-17}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+17}{2*2}=\frac{18}{4}
=4+1/2
$